Rating of Ohmite Resistors in Concorde/K60?

[lgehrig4]

I'm talking about those 2 resistors connecting +/- from the bias jacks. The layout says 1Ohm, but I'm not sure how many watts they need to be.

Thanks!
Jeff

[dave g]

If you assume 50 mA per tube...

Power = Voltage * Current

Ohm's Law states that V = I*R, and in this case R = 1, so we've got that V = I, so power = I^2 = 0.05*0.05 = 0.0025 watts.

A 1/4 watt resistor is capable of dissipating 100 times more power than you need, so don't worry too much about it

[lgehrig4]

Thanks. Must be the reason it's the only resistor on the layout that doesn't mention the wattage