1/4 watt plate R
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1/4 watt plate R
I want to temporarily put a 100k pot in place of the plate resistor on a gain stage with the wiper to the coupling cap to decide what resistor values i need to get the amount of gain i want for a split load setup. But i see the pots i have and most all common pots are listed as 1/4 watt. Is this doable or ill advised?
Re: 1/4 watt plate R
I wouldn't use anything less than 1/2w on a plate resistor.
Tom
Don't let that smoke out!
Don't let that smoke out!
Re: 1/4 watt plate R
In 24mm pots, linear are typically 1/2W. Logs are 1/4. I'd think you'd want linear for this anyway.
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- Posts: 1070
- Joined: Thu Apr 24, 2008 2:10 am
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Re: 1/4 watt plate R
Ok, thanks. Guess i'll just do the old back and fourth swap.
Re: 1/4 watt plate R
What's the foreseen current flowing through it?
It should be less than 1mA, so the dissipated power will be less than 0,1W.
Take also into account the voltage across the pot.
Otherwise, 1/2W pot will be ok.
It should be less than 1mA, so the dissipated power will be less than 0,1W.
Take also into account the voltage across the pot.
Otherwise, 1/2W pot will be ok.
Re: 1/4 watt plate R
I guess I misread the question a bit.
But if you do some loose math, it appears that about .40 watts is dissipated there, not including cathode current.
So 1/2 watt is probably needed.
E2/R=P
But if you do some loose math, it appears that about .40 watts is dissipated there, not including cathode current.
So 1/2 watt is probably needed.
E2/R=P
Tom
Don't let that smoke out!
Don't let that smoke out!
Re: 1/4 watt plate R
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