Push/Pull vs two tubes parallel (Single Ended)

[schaublin65]

Hi

I'd like to thank all the kind people for helping me with my question

"Not a big deal I just pull the glass off and wipe out the excessive electrons with a clean. Cloth"

I have a Buddy Holly Tshirt and a Led Zepplin Tshirt I can use

I might need more advice...

Take care

John

[54Goldtop]

PDF - Are you suggesting that the wattage spread between push-pull and single-ended is not as vast as commonly believed (see below)

[54Goldtop]

Yes, you've summed up a conumdrum!

However, from http://www.valvewizard.co.uk/pp.html does it matter, as two methods of estimating output power are put forward, the latter is more of an estimate but doesn't appear to require cut off?
And we know that transformer action should cause each PP plate to swing between 0v and 2VB+ (ignoring losses).

Much abbreviated summary -
Output power:
P = (HT-Vmin) * Ipeak / 2
= 17.9W
Alternatively
P = 2 * (HT-50)^2 / Rload 15.6W

Maybe the second formula is why amps never seem to put out as much power as they should (or is that just me)?

[pdf64]

I'm not querying the power advantage of PP over SE; even if the 'other' side tube doesn't completely cut off, it's still able to cool off for part of the cycle, thereby allowing lower value load impedances to be used than would be the case for class A PP or SE, and so higher power output.
Rather I'm unclear as to how effectively the differing classes of PP get implemented in practice.

[Tony Bones]

PDF - Are you suggesting that the wattage spread between push-pull and single-ended is not as vast as commonly believed (see below)

What's commonly believed is what's actually been measured over the past century or so.

[54Goldtop]

My apologies, after closer examination realize I misread the formula's and jumped to conclusions -

[Leo_Gnardo]

PDF - Are you suggesting that the wattage spread between push-pull and single-ended is not as vast as commonly believed

Reality has its way of blunting our expectations. Doesn't it.

[Jana]

Leo Gnardo,
reality--I try to avoid it.

[54Goldtop]

With class AB, the zone from plus-ten to minus-ten percent represents the Class A portion where current flows through both tubes. Signals beyond that level will drive each of the tubes alternately into cut-off with the remainder of the signal being amplified by the other tube. Since we’ve reduced the idle current (amps) by biasing the tube away from the class A midpoint, we can now substantially increase the voltage it handles and still keep the dissipation at a level well below what it was for Class A. And as the voltage on the tubes increases, so does the amplitude or amount of clean power they can conduct i.e, greater wattage.

[matt h]

(deleted)

[pdf64]

matt, what's with the mass deletions?
edit - oh dear that's unfortunate.